(4x+3)(2x^2-13x-7)=0

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Solution for (4x+3)(2x^2-13x-7)=0 equation: 


Simplifying
(4x + 3)(2x2 + -13x + -7) = 0

Reorder the terms:
(3 + 4x)(2x2 + -13x + -7) = 0

Reorder the terms:
(3 + 4x)(-7 + -13x + 2x2) = 0

Multiply (3 + 4x) * (-7 + -13x + 2x2)
(3(-7 + -13x + 2x2) + 4x * (-7 + -13x + 2x2)) = 0
((-7 * 3 + -13x * 3 + 2x2 * 3) + 4x * (-7 + -13x + 2x2)) = 0
((-21 + -39x + 6x2) + 4x * (-7 + -13x + 2x2)) = 0
(-21 + -39x + 6x2 + (-7 * 4x + -13x * 4x + 2x2 * 4x)) = 0
(-21 + -39x + 6x2 + (-28x + -52x2 + 8x3)) = 0

Reorder the terms:
(-21 + -39x + -28x + 6x2 + -52x2 + 8x3) = 0

Combine like terms: -39x + -28x = -67x
(-21 + -67x + 6x2 + -52x2 + 8x3) = 0

Combine like terms: 6x2 + -52x2 = -46x2
(-21 + -67x + -46x2 + 8x3) = 0

Solving
-21 + -67x + -46x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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